What are the solutions to the equation 160x-16x^2=0 ?

The solutions to the equation 160x-16x^2=0 are x=0,x=10

Find the zeros of 160x-16x^2=0

The zeros of 160x-16x^2=0 are x=0,x=10

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160 x - 16 x^{2} = 0

x = 0, x = 10

Solution steps

160 x - 16 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 160 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

16 0^{2} - 4 (- 16) \cdot 0 = 160

x_{1, 2} = \frac{- 160 \pm 160}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 160 + 160}{2 ( - 16 )}, x_{2} = \frac{- 160 - 160}{2 ( - 16 )}

x = \frac{- 160 + 160}{2 ( - 16 )} : 0

x = \frac{- 160 - 160}{2 ( - 16 )} : 10

The solutions to the quadratic equation are:

x = 0, x = 10

\frac{2}{7} = \frac{8 x}{7} + \frac{6}{7}

\frac{3 n ^{2} + 2 n ^{2}}{10 n}

(x - 14)^{2} = 2

\frac{7}{4} \cdot 6

2 b^{2} + 3 b = 1

What are the solutions to the equation 160x-16x^2=0 ?
The solutions to the equation 160x-16x^2=0 are x=0,x=10
Find the zeros of 160x-16x^2=0
The zeros of 160x-16x^2=0 are x=0,x=10