What is the answer to (-7x+5)/7+(9x-7)/8 =-1 ?

The answer to (-7x+5)/7+(9x-7)/8 =-1 is x=-47/7

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(-7x+5)/7+(9x-7)/8 =-1

\frac{- 7 x + 5}{7} + \frac{9 x - 7}{8} = - 1

x = - \frac{47}{7}

Decimal Notation

x = - 6.71428 \dots

Solution steps

\frac{- 7 x + 5}{7} + \frac{9 x - 7}{8} = - 1

Multiply by LCM

8 (- 7 x + 5) + 7 (9 x - 7) = - 56

Expand

8 (- 7 x + 5) + 7 (9 x - 7) : 7 x - 9

7 x - 9 = - 56

Move

9

to the right side

7 x = - 47

Divide both sides by

7

x = - \frac{47}{7}

x, y - 4 = - 2 (x + 1)

x, y - 6 = - 2 x

\frac{1}{2} x = 1

\frac{1}{2} x = 3

r - 6 = 6 + 4 r

What is the answer to (-7x+5)/7+(9x-7)/8 =-1 ?
The answer to (-7x+5)/7+(9x-7)/8 =-1 is x=-47/7
Solve for x: (-7x+5)/7+(9x-7)/8 =-1
The solution is x=-47/7