What is the answer to solvefor x,(y^2-4)x-9y=0 ?

The answer to solvefor x,(y^2-4)x-9y=0 is x=(9y)/(y^2-4);\quad y\ne 2,y\ne-2

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solvefor x,(y^2-4)x-9y=0

solve for

x, (y^{2} - 4) x - 9 y = 0

x = \frac{9 y}{y ^{2} - 4}; y \neq = 2, y \neq = - 2

Solution steps

(y^{2} - 4) x - 9 y = 0

Move

9 y

to the right side

(y^{2} - 4) x = 9 y

Divide both sides by

y^{2} - 4; y \neq = 2, y \neq = - 2

x = \frac{9 y}{y ^{2} - 4}; y \neq = 2, y \neq = - 2

\frac{2 n + 7}{- 4} = 3 n

3 (x - 2) = - 7 \frac{1}{2}

12 y + 25 = - 35

4 x = 22 x + 202

What is the answer to solvefor x,(y^2-4)x-9y=0 ?
The answer to solvefor x,(y^2-4)x-9y=0 is x=(9y)/(y^2-4);\quad y\ne 2,y\ne-2