What is the answer to solvefor x,(3-k)x-4(3-k)y=-27 ?

The answer to solvefor x,(3-k)x-4(3-k)y=-27 is x=(-27+4y(3-k))/(3-k);\quad k\ne 3

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solvefor x,(3-k)x-4(3-k)y=-27

solve for

x, (3 - k) x - 4 (3 - k) y = - 27

x = \frac{- 27 + 4 y ( 3 - k )}{3 - k}; k \neq = 3

Solution steps

(3 - k) x - 4 (3 - k) y = - 27

Move

4 (3 - k) y

to the right side

(3 - k) x = - 27 + 4 (3 - k) y

Divide both sides by

3 - k; k \neq = 3

x = \frac{- 27 + 4 y ( 3 - k )}{3 - k}; k \neq = 3

5 (2 y + 1) = 4 y + 10

x, y = m x + n

\frac{x}{5} + 7 = 3

- 8 + \frac{2}{3} x + 4 = 2 x - 5 - x

9 x - 11 = 5 x + 9

What is the answer to solvefor x,(3-k)x-4(3-k)y=-27 ?
The answer to solvefor x,(3-k)x-4(3-k)y=-27 is x=(-27+4y(3-k))/(3-k);\quad k\ne 3