What is the answer to (2a+x)2=4a^2+8ab^2+4b^4 ?

The answer to (2a+x)2=4a^2+8ab^2+4b^4 is x=2(a^2+2ab^2+b^4)-2a

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(2a+x)2=4a^2+8ab^2+4b^4

(2 a + x) 2 = 4 a^{2} + 8 a b^{2} + 4 b^{4}

x = 2 (a^{2} + 2 a b^{2} + b^{4}) - 2 a

Solution steps

(2 a + x) \cdot 2 = 4 a^{2} + 8 a b^{2} + 4 b^{4}

Divide both sides by

2

2 a + x = 2 (a^{2} + 2 a b^{2} + b^{4})

Move

2 a

to the right side

x = 2 (a^{2} + 2 a b^{2} + b^{4}) - 2 a

b, b + g = m

2 (\frac{3}{5} c - 2) + \frac{1}{2} c = 4 - \frac{4}{5} c

\frac{3 d - 2}{8} = - d + 16 \frac{1}{4}

4 x - 1 = 3 x + 1

x, 4 x + 5 y = 40

What is the answer to (2a+x)2=4a^2+8ab^2+4b^4 ?
The answer to (2a+x)2=4a^2+8ab^2+4b^4 is x=2(a^2+2ab^2+b^4)-2a