What are the solutions to the equation x^2-x+12=0 ?

The solutions to the equation x^2-x+12=0 are x= 1/2+i(sqrt(47))/2 ,x= 1/2-i(sqrt(47))/2

Find the zeros of x^2-x+12=0

The zeros of x^2-x+12=0 are x= 1/2+i(sqrt(47))/2 ,x= 1/2-i(sqrt(47))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x + 12 = 0

x = \frac{1}{2} + i \frac{47}{2}, x = \frac{1}{2} - i \frac{47}{2}

Solution steps

x^{2} - x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 12 : 47 i

x_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 47 i}{2 \cdot 1} : \frac{1}{2} + i \frac{47}{2}

x = \frac{- ( - 1 ) - 47 i}{2 \cdot 1} : \frac{1}{2} - i \frac{47}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{47}{2}, x = \frac{1}{2} - i \frac{47}{2}

m^{2} + 24 m + 144

a (3) = \frac{3}{2} (- 2)^{3 - 1}

(x + 4) (x - 5) > (x - 1) (x + 1)

\frac{1}{1 0 ^{- 6}}

2 (6 k - 1) = - 38

What are the solutions to the equation x^2-x+12=0 ?
The solutions to the equation x^2-x+12=0 are x= 1/2+i(sqrt(47))/2 ,x= 1/2-i(sqrt(47))/2
Find the zeros of x^2-x+12=0
The zeros of x^2-x+12=0 are x= 1/2+i(sqrt(47))/2 ,x= 1/2-i(sqrt(47))/2