What is the answer to (2x-1)/3+(x-2)/4-(x+1)/2 =2 ?

The answer to (2x-1)/3+(x-2)/4-(x+1)/2 =2 is x=8

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(2x-1)/3+(x-2)/4-(x+1)/2 =2

\frac{2 x - 1}{3} + \frac{x - 2}{4} - \frac{x + 1}{2} = 2

x = 8

Solution steps

\frac{2 x - 1}{3} + \frac{x - 2}{4} - \frac{x + 1}{2} = 2

Multiply by LCM

4 (2 x - 1) + 3 (x - 2) - 6 (x + 1) = 24

Expand

4 (2 x - 1) + 3 (x - 2) - 6 (x + 1) : 5 x - 16

5 x - 16 = 24

Move

16

to the right side

5 x = 40

Divide both sides by

5

x = 8

6 - 4 (x - 2) = 10

x, y - 2 = 3 (x + 1)

x, y - 3 x = - 4

6 (y + 2) - 4 = - 10

x, 6 x + 3 y = 4 x - 2 y + 8

What is the answer to (2x-1)/3+(x-2)/4-(x+1)/2 =2 ?
The answer to (2x-1)/3+(x-2)/4-(x+1)/2 =2 is x=8
Solve for x: (2x-1)/3+(x-2)/4-(x+1)/2 =2
The solution is x=8