What are the solutions to the equation 5x^2-7x+4=6x+10 ?

The solutions to the equation 5x^2-7x+4=6x+10 are x=3,x=-2/5

Find the zeros of 5x^2-7x+4=6x+10

The zeros of 5x^2-7x+4=6x+10 are x=3,x=-2/5

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5 x^{2} - 7 x + 4 = 6 x + 10

x = 3, x = - \frac{2}{5}

Decimal Notation

x = 3, x = - 0.4

Solution steps

5 x^{2} - 7 x + 4 = 6 x + 10

Move

10

to the left side

5 x^{2} - 7 x - 6 = 6 x

Move

6 x

to the left side

5 x^{2} - 13 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 13)^{2} - 4 \cdot 5 (- 6) = 17

x_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 5}, x_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 5}

x = \frac{- ( - 13 ) + 17}{2 \cdot 5} : 3

x = \frac{- ( - 13 ) - 17}{2 \cdot 5} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{2}{5}

1 + \frac{0.05}{12}

x (7 - x) > 8

\frac{( y ^{2} - a )}{y + 1}

2 \cdot x

c - 3 > 1

What are the solutions to the equation 5x^2-7x+4=6x+10 ?
The solutions to the equation 5x^2-7x+4=6x+10 are x=3,x=-2/5
Find the zeros of 5x^2-7x+4=6x+10
The zeros of 5x^2-7x+4=6x+10 are x=3,x=-2/5