What are the solutions to the equation 4x^2+17x-15=0 ?

The solutions to the equation 4x^2+17x-15=0 are x= 3/4 ,x=-5

Find the zeros of 4x^2+17x-15=0

The zeros of 4x^2+17x-15=0 are x= 3/4 ,x=-5

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4 x^{2} + 17 x - 15 = 0

x = \frac{3}{4}, x = - 5

Solution steps

4 x^{2} + 17 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 (- 15) = 23

x_{1, 2} = \frac{- 17 \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 23}{2 \cdot 4}, x_{2} = \frac{- 17 - 23}{2 \cdot 4}

x = \frac{- 17 + 23}{2 \cdot 4} : \frac{3}{4}

x = \frac{- 17 - 23}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - 5

9 x^{2} - 6 x y + y^{2}

(\frac{4 w ^{3}}{2 z ^{2}})^{3}

4 d - 6 < 18

4 n^{2} y - 8 n y - 4 n y^{2}

\frac{2}{3} + \frac{3 m}{5} = \frac{31}{15}

What are the solutions to the equation 4x^2+17x-15=0 ?
The solutions to the equation 4x^2+17x-15=0 are x= 3/4 ,x=-5
Find the zeros of 4x^2+17x-15=0
The zeros of 4x^2+17x-15=0 are x= 3/4 ,x=-5