What are the solutions to the equation (x-3)^2+5=21 ?

The solutions to the equation (x-3)^2+5=21 are x=7,x=-1

Find the zeros of (x-3)^2+5=21

The zeros of (x-3)^2+5=21 are x=7,x=-1

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(x - 3)^{2} + 5 = 21

x = 7, x = - 1

Solution steps

(x - 3)^{2} + 5 = 21

Move

5

to the right side

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- (x + y)

x y - 3 y + x - 3

\frac{2}{15} x - \frac{3}{2} < \frac{2}{5} x + \frac{7}{6}

(\frac{2}{2}) (\frac{3}{3})

What are the solutions to the equation (x-3)^2+5=21 ?
The solutions to the equation (x-3)^2+5=21 are x=7,x=-1
Find the zeros of (x-3)^2+5=21
The zeros of (x-3)^2+5=21 are x=7,x=-1