What is the answer to log_{1/143}(1/9)=-2y ?

The answer to log_{1/143}(1/9)=-2y is y=-(log_{1/143}(1/9))/2

Solve for y: log_{1/143}(1/9)=-2y

The solution is y=-(log_{1/143}(1/9))/2

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lo g_{\frac{1}{143}} (\frac{1}{9}) = - 2 y

y = - \frac{lo g _{\frac{1}{143}} ( \frac{1}{9} )}{2}

Decimal

y = - 0.22136 \dots

Solution steps

lo g_{\frac{1}{143}} (\frac{1}{9}) = - 2 y

Switch sides

- 2 y = lo g_{\frac{1}{143}} (\frac{1}{9})

Divide both sides by

- 2

y = - \frac{lo g _{\frac{1}{143}} ( \frac{1}{9} )}{2}

x + \frac{3 x + 2}{2} = \frac{1 + x}{4}

- 5 = \frac{3}{4} t

x, 3 x - y - 6 = 0

x - \frac{8}{3} x = - 10

x, 3 x - y - 2 = 0

What is the answer to log_{1/143}(1/9)=-2y ?
The answer to log_{1/143}(1/9)=-2y is y=-(log_{1/143}(1/9))/2
Solve for y: log_{1/143}(1/9)=-2y
The solution is y=-(log_{1/143}(1/9))/2