What are the solutions to the equation 216x-12x^2=0 ?

The solutions to the equation 216x-12x^2=0 are x=0,x=18

Find the zeros of 216x-12x^2=0

The zeros of 216x-12x^2=0 are x=0,x=18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

216 x - 12 x^{2} = 0

x = 0, x = 18

Solution steps

216 x - 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 x^{2} + 216 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 216 \pm 21 6 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

21 6^{2} - 4 (- 12) \cdot 0 = 216

x_{1, 2} = \frac{- 216 \pm 216}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 216 + 216}{2 ( - 12 )}, x_{2} = \frac{- 216 - 216}{2 ( - 12 )}

x = \frac{- 216 + 216}{2 ( - 12 )} : 0

x = \frac{- 216 - 216}{2 ( - 12 )} : 18

The solutions to the quadratic equation are:

x = 0, x = 18

2 + 2 u \leq 6

x + \frac{5}{3} = \frac{2}{3}

(2 x^{3} y)^{6}

\frac{3}{4} x - \frac{1}{2} = 1

0.22 = y + (1 - y) 0.08

What are the solutions to the equation 216x-12x^2=0 ?
The solutions to the equation 216x-12x^2=0 are x=0,x=18
Find the zeros of 216x-12x^2=0
The zeros of 216x-12x^2=0 are x=0,x=18