What is the answer to 1/2 [1+1/4 (3z-1)]=(2z)/3-1/2 ?

The answer to 1/2 [1+1/4 (3z-1)]=(2z)/3-1/2 is z=3

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1/2 [1+1/4 (3z-1)]=(2z)/3-1/2

\frac{1}{2} [1 + \frac{1}{4} (3 z - 1)] = \frac{2 z}{3} - \frac{1}{2}

z = 3

Solution steps

\frac{1}{2} [1 + \frac{1}{4} (3 z - 1)] = \frac{2 z}{3} - \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{1 \cdot ( 1 + \frac{1}{4} ( 3 z - 1 ) )}{2} = \frac{2 z}{3} - \frac{1}{2}

1 \cdot (1 + \frac{1}{4} (3 z - 1)) = 1 + \frac{1}{4} (3 z - 1)

\frac{1 + \frac{1}{4} ( 3 z - 1 )}{2} = \frac{2 z}{3} - \frac{1}{2}

Move

\frac{2 z}{3}

to the left side

\frac{- 7 z + 9}{24} = - \frac{1}{2}

Multiply both sides by

24

- 7 z + 9 = - 12

Move

9

to the right side

- 7 z = - 21

Divide both sides by

- 7

z = 3

x, 2 x y + 2 y = 0

- 2.38 + 3.9 k = 2.17 + 3.2 k + 2.45

- 6 n + 22 = - 4 n + 14

7 x = 3 x + 12

x, 5 x - 4 y = 2

What is the answer to 1/2 [1+1/4 (3z-1)]=(2z)/3-1/2 ?
The answer to 1/2 [1+1/4 (3z-1)]=(2z)/3-1/2 is z=3
Solve for z: 1/2 [1+1/4 (3z-1)]=(2z)/3-1/2
The solution is z=3