What is (2s^3t^{-1})(1/4 s^6)(16t^4) ?

The solution to (2s^3t^{-1})(1/4 s^6)(16t^4) is 8s^9t^3

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simplify (2s^3t^{-1})(1/4 s^6)(16t^4)

simplify

(2 s^{3} t^{- 1}) (\frac{1}{4} s^{6}) (16 t^{4})

8 s^{9} t^{3}

Solution steps

(2 s^{3} t^{- 1}) (\frac{1}{4} s^{6}) (16 t^{4})

Simplify

2 s^{3} t^{- 1} : \frac{2 s ^{3}}{t}

= \frac{2 s ^{3}}{t} \cdot \frac{1}{4} s^{6} \cdot 16 t^{4}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{2 s ^{3} \cdot 1 \cdot s ^{6} \cdot 16 t ^{4}}{t \cdot 4}

Multiply the numbers:

2 \cdot 1 \cdot 16 = 32

= \frac{32 s ^{3} s ^{6} t ^{4}}{t \cdot 4}

Factor the number:

32 = 4 \cdot 8

= \frac{4 \cdot 8 s ^{3} s ^{6} t ^{4}}{t \cdot 4}

Cancel the common factor:

4

= \frac{8 s ^{3} s ^{6} t ^{4}}{t}

Simplify

\frac{t ^{4}}{t} : t^{3}

= 8 s^{3} s^{6} t^{3}

Simplify

s^{3} s^{6} : s^{9}

= 8 s^{9} t^{3}

5 [4 - 2 (3 - w)] = 8 - 4 (2 w - 1)

2 (x + 7) - 34 = 4 x - 11 x + 4 (x - 1)

\frac{π}{4} + 4 π

7 (7 x + 8) = 4 (3 x + 5) + 221

3 x^{2} - 5 x + 9 = 0

What is (2s^3t^{-1})(1/4 s^6)(16t^4) ?
The solution to (2s^3t^{-1})(1/4 s^6)(16t^4) is 8s^9t^3