What is the answer to (3n+2)/8 =(3n-2)/4 ?

The answer to (3n+2)/8 =(3n-2)/4 is n=2

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(3n+2)/8 =(3n-2)/4

\frac{3 n + 2}{8} = \frac{3 n - 2}{4}

n = 2

Solution steps

\frac{3 n + 2}{8} = \frac{3 n - 2}{4}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 n + 2) \cdot 4 = 8 (3 n - 2)

Expand

(3 n + 2) \cdot 4 : 12 n + 8

Expand

8 (3 n - 2) : 24 n - 16

12 n + 8 = 24 n - 16

Move

8

to the right side

12 n = 24 n - 24

Move

24 n

to the left side

- 12 n = - 24

Divide both sides by

- 12

n = 2

0 - y = 2

x, 5 x - 4 y = 19

6 = \frac{a}{4 + 2}

- s = 4 (\frac{1}{2} s + 4)

lo g_{15} (15) 15 = n

What is the answer to (3n+2)/8 =(3n-2)/4 ?
The answer to (3n+2)/8 =(3n-2)/4 is n=2
Solve for n: (3n+2)/8 =(3n-2)/4
The solution is n=2