What is the answer to solvefor x,y-2xy-y^2=0 ?

The answer to solvefor x,y-2xy-y^2=0 is x=-(-1+y)/2 ;\quad y\ne 0

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solvefor x,y-2xy-y^2=0

solve for

x, y - 2 x y - y^{2} = 0

x = - \frac{- 1 + y}{2}; y \neq = 0

Solution steps

y - 2 x y - y^{2} = 0

Move

y

to the right side

- 2 x y - y^{2} = - y

Move

y^{2}

to the right side

- 2 x y = - y + y^{2}

Divide both sides by

- 2 y; y \neq = 0

x = - \frac{- 1 + y}{2}; y \neq = 0

6 (2 x + 1) = 18

(12 x - 231) + (15 x - 273) + (10 x - 234) = 150

5 (x + 5) = 2 x + 40

y, x + 5 y = 5

a, f = ab

What is the answer to solvefor x,y-2xy-y^2=0 ?
The answer to solvefor x,y-2xy-y^2=0 is x=-(-1+y)/2 ;\quad y\ne 0