What is the answer to solvefor c,x^2+3y^2=cy ?

The answer to solvefor c,x^2+3y^2=cy is c=(x^2+3y^2)/y ;\quad y\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor c,x^2+3y^2=cy

solve for

c, x^{2} + 3 y^{2} = cy

c = \frac{x ^{2} + 3 y ^{2}}{y}; y \neq = 0

Solution steps

x^{2} + 3 y^{2} = cy

Switch sides

cy = x^{2} + 3 y^{2}

Divide both sides by

y; y \neq = 0

c = \frac{x ^{2} + 3 y ^{2}}{y}; y \neq = 0

2 (y - 3) = 4

x, 3 x + 5 y = 6

\frac{x - 1}{3} - 1 = \frac{x + 1}{6} - \frac{x}{2}

f, f = \frac{y - 3 x}{x - 2 y}

15 x - 10 = - 9 x + 2

What is the answer to solvefor c,x^2+3y^2=cy ?
The answer to solvefor c,x^2+3y^2=cy is c=(x^2+3y^2)/y ;\quad y\ne 0