What is the answer to solvefor x,y=mx+b_{2} ?

The answer to solvefor x,y=mx+b_{2} is x=(y-b_{2})/m ;\quad m\ne 0

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solvefor x,y=mx+b_{2}

solve for

x, y = m x + b_{2}

x = \frac{y - b _{2}}{m}; m \neq = 0

Solution steps

y = m x + b_{2}

Switch sides

m x + b_{2} = y

Move

b_{2}

to the right side

m x = y - b_{2}

Divide both sides by

m; m \neq = 0

x = \frac{y - b _{2}}{m}; m \neq = 0

5 - 2 x = 0

\frac{x}{6} = 11

0.6 = 1.1 - \frac{a}{3.4}

3 x - 3 + 2 (x - 2) = x - 3

12 x + 10 = - 38

What is the answer to solvefor x,y=mx+b_{2} ?
The answer to solvefor x,y=mx+b_{2} is x=(y-b_{2})/m ;\quad m\ne 0