What is the answer to (5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t ?

The answer to (5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t is t=-5/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t

(5 t - 1) \cdot (5 t + 1) - 21 t^{2} + 15 = (2 t - 3)^{2} + 5 t

t = - \frac{5}{7}

Decimal Notation

t = - 0.71428 \dots

Solution steps

(5 t - 1) (5 t + 1) - 21 t^{2} + 15 = (2 t - 3)^{2} + 5 t

Expand

(5 t - 1) (5 t + 1) - 21 t^{2} + 15 : 4 t^{2} + 14

Expand

(2 t - 3)^{2} + 5 t : 4 t^{2} - 7 t + 9

4 t^{2} + 14 = 4 t^{2} - 7 t + 9

Move

14

to the right side

4 t^{2} = 4 t^{2} - 7 t - 5

Subtract

4 t^{2} - 7 t

from both sides

4 t^{2} - (4 t^{2} - 7 t) = 4 t^{2} - 7 t - 5 - (4 t^{2} - 7 t)

Simplify

7 t = - 5

Divide both sides by

7

t = - \frac{5}{7}

\frac{x - 2}{2} + \frac{x - 4}{2} = 1

(x - 7) (8 x - 4) = (4 x - 5) (2 x + 7)

x, 3 x - 5 y = - 2

24 - 5 w = 9

x, y - 3 x = 19

What is the answer to (5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t ?
The answer to (5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t is t=-5/7
Solve for t: (5t-1)*(5t+1)-21t^2+15=(2t-3)^2+5t
The solution is t=-5/7