What is the answer to solvefor a,2a-3b+c=11 ?

The answer to solvefor a,2a-3b+c=11 is a=(11+3b-c)/2

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solvefor a,2a-3b+c=11

solve for

a, 2 a - 3 b + c = 11

a = \frac{11 + 3 b - c}{2}

Solution steps

2 a - 3 b + c = 11

Move

3 b

to the right side

2 a + c = 11 + 3 b

Move

c

to the right side

2 a = 11 + 3 b - c

Divide both sides by

2

a = \frac{11 + 3 b - c}{2}

b, a = \frac{b + c}{d}

6 x - 3 + 5 x = 13 x - 19

C = 25 + 1.8 (15)

x, 6 x + 14 y = 34

x, 2 x + 3 y + 4 = 0

What is the answer to solvefor a,2a-3b+c=11 ?
The answer to solvefor a,2a-3b+c=11 is a=(11+3b-c)/2