What is the answer to 5+4x-x^2=9-(x-2)^2 ?

The answer to 5+4x-x^2=9-(x-2)^2 is True for all x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5+4x-x^2=9-(x-2)^2

5 + 4 x - x^{2} = 9 - (x - 2)^{2}

True for all x

Solution steps

5 + 4 x - x^{2} = 9 - (x - 2)^{2}

Expand

9 - (x - 2)^{2} : - x^{2} + 4 x + 5

5 + 4 x - x^{2} = - x^{2} + 4 x + 5

Move

5

to the right side

4 x - x^{2} = - x^{2} + 4 x

Subtract

- x^{2} + 4 x

from both sides

4 x - x^{2} - (- x^{2} + 4 x) = - x^{2} + 4 x - (- x^{2} + 4 x)

Simplify

0 = 0

Both sides are equal

True for all x

g, y = \frac{1}{2} g t^{2}

4 b + 8 = 6 b - 4

x - 872 + \frac{9 x}{100} = 0

4 (3 - x) + 8 = 2 + 2 (x - 3)

x, y - 1 = - 2 (x - 2)

What is the answer to 5+4x-x^2=9-(x-2)^2 ?
The answer to 5+4x-x^2=9-(x-2)^2 is True for all x
Solve for x: 5+4x-x^2=9-(x-2)^2
The solution is True for all x