What is the answer to x(3x-2)=(3x+1)(x-2) ?

The answer to x(3x-2)=(3x+1)(x-2) is x=-2/3

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x(3x-2)=(3x+1)(x-2)

x (3 x - 2) = (3 x + 1) (x - 2)

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

x (3 x - 2) = (3 x + 1) (x - 2)

Expand

x (3 x - 2) : 3 x^{2} - 2 x

Expand

(3 x + 1) (x - 2) : 3 x^{2} - 5 x - 2

3 x^{2} - 2 x = 3 x^{2} - 5 x - 2

Subtract

3 x^{2} - 5 x

from both sides

3 x^{2} - 2 x - (3 x^{2} - 5 x) = 3 x^{2} - 5 x - 2 - (3 x^{2} - 5 x)

Simplify

3 x = - 2

Divide both sides by

3

x = - \frac{2}{3}

7 s + 45 = - 32

x + 3 x + 5 x + 7 x + 15 x = 128

15 m + 2 = 4.25

x, 2 x + 3 y - 5 z = - 12

2 (x - 2) = 0

What is the answer to x(3x-2)=(3x+1)(x-2) ?
The answer to x(3x-2)=(3x+1)(x-2) is x=-2/3
Solve for x: x(3x-2)=(3x+1)(x-2)
The solution is x=-2/3