What is the answer to log_{10}(2)(x)+log_{10}(2)(x-2)=3 ?

The answer to log_{10}(2)(x)+log_{10}(2)(x-2)=3 is x=(3+2log_{10}(2))/(2log_{10)(2)}

Solve for x: log_{10}(2)(x)+log_{10}(2)(x-2)=3

The solution is x=(3+2log_{10}(2))/(2log_{10)(2)}

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lo g_{10} (2) (x) + lo g_{10} (2) (x - 2) = 3

x = \frac{3 + 2 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

Decimal Notation

x = 5.98289 \dots

Solution steps

lo g_{10} (2) (x) + lo g_{10} (2) (x - 2) = 3

lo g_{10} (2) x + lo g_{10} (2) (x - 2) = 3

Expand

lo g_{10} (2) (x - 2) : lo g_{10} (2) x - 2 lo g_{10} (2)

lo g_{10} (2) x + lo g_{10} (2) x - 2 lo g_{10} (2) = 3

Add similar elements:

lo g_{10} (2) x + lo g_{10} (2) x = 2 lo g_{10} (2) x

2 lo g_{10} (2) x - 2 lo g_{10} (2) = 3

Move

2 lo g_{10} (2)

to the right side

2 lo g_{10} (2) x = 3 + 2 lo g_{10} (2)

Divide both sides by

2 lo g_{10} (2)

x = \frac{3 + 2 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

x, 2 y = 4 x - 8

\frac{5}{2} = \frac{x}{10}

- 12 + 5 (- 2 u - 20) = 3 (u + 19)

- 13 - \frac{2}{11} x = - 9

x, 4 x + 6 y = 36

What is the answer to log_{10}(2)(x)+log_{10}(2)(x-2)=3 ?
The answer to log_{10}(2)(x)+log_{10}(2)(x-2)=3 is x=(3+2log_{10}(2))/(2log_{10)(2)}
Solve for x: log_{10}(2)(x)+log_{10}(2)(x-2)=3
The solution is x=(3+2log_{10}(2))/(2log_{10)(2)}