What is (2x^3y^{-1/4})^2(8y^{-3/2})^{-1/3} ?

The solution to (2x^3y^{-1/4})^2(8y^{-3/2})^{-1/3} is 2x^6

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simplify (2x^3y^{-1/4})^2(8y^{-3/2})^{-1/3}

simplify

(2 x^{3} y^{- \frac{1}{4}})^{2} (8 y^{- \frac{3}{2}})^{- \frac{1}{3}}

2 x^{6}

Solution steps

(2 x^{3} y^{- \frac{1}{4}})^{2} (8 y^{- \frac{3}{2}})^{- \frac{1}{3}}

Simplify

(2 x^{3} y^{- \frac{1}{4}})^{2} : \frac{4 x ^{6}}{y ^{\frac{1}{2}}}

= \frac{4 x ^{6}}{y ^{\frac{1}{2}}} (8 y^{- \frac{3}{2}})^{- \frac{1}{3}}

Simplify

(8 y^{- \frac{3}{2}})^{- \frac{1}{3}} : \frac{y ^{\frac{1}{2}}}{2}

= \frac{4 x ^{6}}{y ^{\frac{1}{2}}} \cdot \frac{y ^{\frac{1}{2}}}{2}

Cross-cancel common factor:

y^{\frac{1}{2}}

= \frac{4 x ^{6}}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 x^{6}

4 (3 + c) + c = c + 4

- 3 x^{2} + 18 x + 48

3 x - 7 (x + 3) < - 13

2 w^{2} - w = 28

∣ x - 6 ∣ \leq 6

What is (2x^3y^{-1/4})^2(8y^{-3/2})^{-1/3} ?
The solution to (2x^3y^{-1/4})^2(8y^{-3/2})^{-1/3} is 2x^6