What is the answer to 3x^2+3-6x=3(x-1)^2 ?

The answer to 3x^2+3-6x=3(x-1)^2 is True for all x

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3x^2+3-6x=3(x-1)^2

3 x^{2} + 3 - 6 x = 3 (x - 1)^{2}

True for all x

Solution steps

3 x^{2} + 3 - 6 x = 3 (x - 1)^{2}

Expand

3 (x - 1)^{2} : 3 x^{2} - 6 x + 3

3 x^{2} + 3 - 6 x = 3 x^{2} - 6 x + 3

Move

3

to the right side

3 x^{2} - 6 x = 3 x^{2} - 6 x

Subtract

3 x^{2} - 6 x

from both sides

3 x^{2} - 6 x - (3 x^{2} - 6 x) = 3 x^{2} - 6 x - (3 x^{2} - 6 x)

Simplify

0 = 0

Both sides are equal

True for all x

x, - 5 x + 4 y = 3

p, A = p + p r t

- 15 + 5 = 2 x

3 r a = d^{2} + 4

x, f = - \infty

What is the answer to 3x^2+3-6x=3(x-1)^2 ?
The answer to 3x^2+3-6x=3(x-1)^2 is True for all x
Solve for x: 3x^2+3-6x=3(x-1)^2
The solution is True for all x