What is the answer to 2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)} ?

The answer to 2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)} is x=11

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2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)}

2 x + 3 (- x^{2} - 1) = - {3 x^{2} + 2 (x - 1) - 3 (x + 2)}

x = 11

Solution steps

2 x + 3 (- x^{2} - 1) = - {3 x^{2} + 2 (x - 1) - 3 (x + 2)}

Expand

3 (- x^{2} - 1) : - 3 x^{2} - 3

2 x - 3 x^{2} - 3 = - {3 x^{2} + 2 (x - 1) - 3 (x + 2)}

Expand

- (3 x^{2} + 2 (x - 1) - 3 (x + 2)) : - 3 x^{2} + x + 8

2 x - 3 x^{2} - 3 = - 3 x^{2} + x + 8

Move

3

to the right side

2 x - 3 x^{2} = - 3 x^{2} + x + 11

Subtract

- 3 x^{2} + x

from both sides

2 x - 3 x^{2} - (- 3 x^{2} + x) = - 3 x^{2} + x + 11 - (- 3 x^{2} + x)

Simplify

x = 11

\frac{a - 8}{12} = \frac{2 a + 5}{3}

x, 3 y - 2 x = 7

18 x - 3 = 0

\frac{2 t - 9}{3} = \frac{3 t + 4}{2}

2 x - 6 = 18

What is the answer to 2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)} ?
The answer to 2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)} is x=11
Solve for x: 2x+3(-x^2-1)=-{3x^2+2(x-1)-3(x+2)}
The solution is x=11