What is the answer to p=log_{10}(10+1980/2) ?

The answer to p=log_{10}(10+1980/2) is p=3

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p=log_{10}(10+1980/2)

p = lo g_{10} (10 + \frac{1980}{2})

p = 3

Solution steps

p = lo g_{10} (10 + \frac{1980}{2})

Simplify

lo g_{10} (10 + \frac{1980}{2}) : 3

p = 3

3 (x - 5) = 2 (x + 2) + 5 x - 11

x, x y + x = 2

x - 9.5 = - 10.5

1.4 x - (2 x - 1) + x = 2 x - (13 - x) - x

x, 10 x + 4 y = 20

What is the answer to p=log_{10}(10+1980/2) ?
The answer to p=log_{10}(10+1980/2) is p=3
Solve for p: p=log_{10}(10+1980/2)
The solution is p=3