What are the solutions to the equation 7x^2-43x+6=0 ?

The solutions to the equation 7x^2-43x+6=0 are x=6,x= 1/7

Find the zeros of 7x^2-43x+6=0

The zeros of 7x^2-43x+6=0 are x=6,x= 1/7

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7 x^{2} - 43 x + 6 = 0

x = 6, x = \frac{1}{7}

Solution steps

7 x^{2} - 43 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 43 ) \pm ( - 43 ) ^{2} - 4 \cdot 7 \cdot 6}{2 \cdot 7}

(- 43)^{2} - 4 \cdot 7 \cdot 6 = 41

x_{1, 2} = \frac{- ( - 43 ) \pm 41}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 43 ) + 41}{2 \cdot 7}, x_{2} = \frac{- ( - 43 ) - 41}{2 \cdot 7}

x = \frac{- ( - 43 ) + 41}{2 \cdot 7} : 6

x = \frac{- ( - 43 ) - 41}{2 \cdot 7} : \frac{1}{7}

The solutions to the quadratic equation are:

x = 6, x = \frac{1}{7}

75 k^{4}

\frac{- 6}{9}

x^{2} + 4 x - 49 = 4 x

\frac{7}{2 - 3 x} - 9 = 0

4 (k - 8) = - 32 + 4 k

What are the solutions to the equation 7x^2-43x+6=0 ?
The solutions to the equation 7x^2-43x+6=0 are x=6,x= 1/7
Find the zeros of 7x^2-43x+6=0
The zeros of 7x^2-43x+6=0 are x=6,x= 1/7