What is the answer to 2x(3x-5)=3(2x^2-3) ?

The answer to 2x(3x-5)=3(2x^2-3) is x= 9/10

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2x(3x-5)=3(2x^2-3)

2 x (3 x - 5) = 3 (2 x^{2} - 3)

x = \frac{9}{10}

Decimal Notation

x = 0.9

Solution steps

2 x (3 x - 5) = 3 (2 x^{2} - 3)

Expand

2 x (3 x - 5) : 6 x^{2} - 10 x

Expand

3 (2 x^{2} - 3) : 6 x^{2} - 9

6 x^{2} - 10 x = 6 x^{2} - 9

Move

6 x^{2}

to the left side

- 10 x = - 9

Divide both sides by

- 10

x = \frac{9}{10}

8 x + 2 + 3 x + 5 = x + 12

y, 3 x - 2 y = 10

\frac{3 x + 5}{4} - \frac{2 x - 3}{3} = 3

lo g_{10} (\frac{1}{10000000}) = - 7

3 (y + 3) = 14

What is the answer to 2x(3x-5)=3(2x^2-3) ?
The answer to 2x(3x-5)=3(2x^2-3) is x= 9/10
Solve for x: 2x(3x-5)=3(2x^2-3)
The solution is x= 9/10