What is the answer to (2x)/7+4/3 = x/7-2/5 ?

The answer to (2x)/7+4/3 = x/7-2/5 is x=-182/15

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(2x)/7+4/3 = x/7-2/5

\frac{2 x}{7} + \frac{4}{3} = \frac{x}{7} - \frac{2}{5}

x = - \frac{182}{15}

Decimal Notation

x = - 12.13333 \dots

Solution steps

\frac{2 x}{7} + \frac{4}{3} = \frac{x}{7} - \frac{2}{5}

Move

\frac{x}{7}

to the left side

\frac{x}{7} + \frac{4}{3} = - \frac{2}{5}

Move

\frac{4}{3}

to the right side

\frac{x}{7} = - \frac{26}{15}

Multiply both sides by

7

x = - \frac{182}{15}

2 (x + 1) = 0

2 r - 3 = 1

2 (x + 2) = 0

y = (3)^{2}

3 x - x + 4 = 5 x - 8

What is the answer to (2x)/7+4/3 = x/7-2/5 ?
The answer to (2x)/7+4/3 = x/7-2/5 is x=-182/15
Solve for x: (2x)/7+4/3 = x/7-2/5
The solution is x=-182/15