What is the answer to solvefor C,y=x^2+Cx ?

The answer to solvefor C,y=x^2+Cx is C=(y-x^2)/x ;\quad x\ne 0

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solvefor C,y=x^2+Cx

solve for

C, y = x^{2} + C x

C = \frac{y - x ^{2}}{x}; x \neq = 0

Solution steps

y = x^{2} + C x

Switch sides

x^{2} + C x = y

Move

x^{2}

to the right side

C x = y - x^{2}

Divide both sides by

x; x \neq = 0

C = \frac{y - x ^{2}}{x}; x \neq = 0

4 = \frac{x}{3}

12 t = - 132

\frac{2 y - 15}{3} = \frac{18 - y}{9}

2 x + 3 x = 0

y, 3 x + 6 y = 24

What is the answer to solvefor C,y=x^2+Cx ?
The answer to solvefor C,y=x^2+Cx is C=(y-x^2)/x ;\quad x\ne 0