What are the solutions to the equation 9a^2-55=-18a ?

The solutions to the equation 9a^2-55=-18a are a= 5/3 ,a=-11/3

Find the zeros of 9a^2-55=-18a

The zeros of 9a^2-55=-18a are a= 5/3 ,a=-11/3

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9 a^{2} - 55 = - 18 a

a = \frac{5}{3}, a = - \frac{11}{3}

Solution steps

9 a^{2} - 55 = - 18 a

Move

18 a

to the left side

9 a^{2} - 55 + 18 a = 0

Write in the standard form

a x^{2} + b x + c = 0

9 a^{2} + 18 a - 55 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 55 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 55) = 48

a_{1, 2} = \frac{- 18 \pm 48}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 18 + 48}{2 \cdot 9}, a_{2} = \frac{- 18 - 48}{2 \cdot 9}

a = \frac{- 18 + 48}{2 \cdot 9} : \frac{5}{3}

a = \frac{- 18 - 48}{2 \cdot 9} : - \frac{11}{3}

The solutions to the quadratic equation are:

a = \frac{5}{3}, a = - \frac{11}{3}

2 x - \frac{2}{3} = \frac{10 x}{3} + 2

\frac{3}{∣ x - 3 ∣} < 3

90 - 12 b

\frac{\frac{9}{25}}{1.5}

12 5^{- \frac{1}{3}}

What are the solutions to the equation 9a^2-55=-18a ?
The solutions to the equation 9a^2-55=-18a are a= 5/3 ,a=-11/3
Find the zeros of 9a^2-55=-18a
The zeros of 9a^2-55=-18a are a= 5/3 ,a=-11/3