What are the solutions to the equation 81x^2=4 ?

The solutions to the equation 81x^2=4 are x= 2/9 ,x=-2/9

Find the zeros of 81x^2=4

The zeros of 81x^2=4 are x= 2/9 ,x=-2/9

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81 x^{2} = 4

x = \frac{2}{9}, x = - \frac{2}{9}

Solution steps

81 x^{2} = 4

Divide both sides by

81

x^{2} = \frac{4}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{81}, x = - \frac{4}{81}

\frac{4}{81} = \frac{2}{9}

- \frac{4}{81} = - \frac{2}{9}

x = \frac{2}{9}, x = - \frac{2}{9}

(0.903 \cdot 200) + (70 \cdot 4.179) = t (0.903 + 4.179)

\frac{3}{4} f + 5 = - 5

(5 m^{2} - 3 m^{2} + 6) (- 3 m + 2)

6 w^{2} + 24 w = 0

b^{2} - 4 b - 45

What are the solutions to the equation 81x^2=4 ?
The solutions to the equation 81x^2=4 are x= 2/9 ,x=-2/9
Find the zeros of 81x^2=4
The zeros of 81x^2=4 are x= 2/9 ,x=-2/9