What is the answer to x^3-1=(x-1)(x^2+x+1) ?

The answer to x^3-1=(x-1)(x^2+x+1) is True for all x

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x^3-1=(x-1)(x^2+x+1)

x^{3} - 1 = (x - 1) (x^{2} + x + 1)

True for all x

Solution steps

x^{3} - 1 = (x - 1) (x^{2} + x + 1)

Expand

(x - 1) (x^{2} + x + 1) : x^{3} - 1

x^{3} - 1 = x^{3} - 1

Move

1

to the right side

x^{3} = x^{3}

Move

x^{3}

to the left side

0 = 0

Both sides are equal

True for all x

f, a = \frac{f}{m}

x, 5 x - y = - 1

42 - x = 35

7 x + 7 (6 x - 5) = 112

a, Y = - n^{3} + \frac{3}{4} a

What is the answer to x^3-1=(x-1)(x^2+x+1) ?
The answer to x^3-1=(x-1)(x^2+x+1) is True for all x
Solve for x: x^3-1=(x-1)(x^2+x+1)
The solution is True for all x