What is the answer to (3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1) ?

The answer to (3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1) is x=0

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(3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1)

(3 x - 2)^{3} - (3 x - 4) (6 x - 5) - 45 x^{2} = 9 x^{2} (3 x - 5) - 10 (x + 3) - 2 (6 x - 1) (6 x + 1)

x = 0

Solution steps

(3 x - 2)^{3} - (3 x - 4) (6 x - 5) - 45 x^{2} = 9 x^{2} (3 x - 5) - 10 (x + 3) - 2 (6 x - 1) (6 x + 1)

Expand

(3 x - 2)^{3} - (3 x - 4) (6 x - 5) - 45 x^{2} : 27 x^{3} - 117 x^{2} + 75 x - 28

Expand

9 x^{2} (3 x - 5) - 10 (x + 3) - 2 (6 x - 1) (6 x + 1) : 27 x^{3} - 117 x^{2} - 10 x - 28

27 x^{3} - 117 x^{2} + 75 x - 28 = 27 x^{3} - 117 x^{2} - 10 x - 28

Move

28

to the right side

27 x^{3} - 117 x^{2} + 75 x = 27 x^{3} - 117 x^{2} - 10 x

Subtract

27 x^{3} - 117 x^{2} - 10 x

from both sides

27 x^{3} - 117 x^{2} + 75 x - (27 x^{3} - 117 x^{2} - 10 x) = 27 x^{3} - 117 x^{2} - 10 x - (27 x^{3} - 117 x^{2} - 10 x)

Simplify

85 x = 0

Divide both sides by

85

x = 0

2 (3 + 4 x) + 2 x = 10 x + 6

4 + 3 x - 6 = 3 x + 2 - x

x, 2 x + 5 = y + 12

5 (x + 1) + 3 (x - 2) = 3 (3 x - 2)

a, a \cdot (t + z) = 45 z + 67

What is the answer to (3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1) ?
The answer to (3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1) is x=0
Solve for x: (3x-2)^3-(3x-4)(6x-5)-45x^2=9x^2(3x-5)-10(x+3)-2(6x-1)(6x+1)
The solution is x=0