What is the answer to r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2 ?

The answer to r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2 is r= 5/4

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r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2

r = (- \frac{1}{2})^{2} + (- \frac{3}{2})^{2}

r = \frac{5}{4}

Solution steps

r = (- \frac{1}{2})^{2} + (- \frac{3}{2})^{2}

Simplify

(- \frac{1}{2})^{2} + (- \frac{3}{2})^{2} : \frac{5}{4}

r = \frac{5}{4}

x, y = 2 x + 3

2 (x - 5) = 0

64 x - 16 = 16 (4 x - 1)

a, u = a + (n - 1) d

6 x + 4 = 52

What is the answer to r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2 ?
The answer to r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2 is r= 5/4
Solve for r: r=sqrt((-1/2)^2)+(-(sqrt(3))/2)^2
The solution is r= 5/4