What are the solutions to the equation 4a^2=7a ?

The solutions to the equation 4a^2=7a are a=0,a= 7/4

Find the zeros of 4a^2=7a

The zeros of 4a^2=7a are a=0,a= 7/4

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4 a^{2} = 7 a

a = 0, a = \frac{7}{4}

Solution steps

4 a^{2} = 7 a

Move

7 a

to the left side

4 a^{2} - 7 a = 0

Factor

4 a^{2} - 7 a : a (4 a - 7)

a (4 a - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0 or 4 a - 7 = 0

Solve

4 a - 7 = 0 : a = \frac{7}{4}

The solutions to the quadratic equation are:

a = 0, a = \frac{7}{4}

\frac{2 x}{5} = 6

∣ y - 2 ∣ > 4

24 a^{2} - 54 b^{2}

3 (d + 1) = 9

16 - c^{4}

What are the solutions to the equation 4a^2=7a ?
The solutions to the equation 4a^2=7a are a=0,a= 7/4
Find the zeros of 4a^2=7a
The zeros of 4a^2=7a are a=0,a= 7/4