What is the answer to (x+2)/3+(x-4)/6 =1 ?

The answer to (x+2)/3+(x-4)/6 =1 is x=2

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(x+2)/3+(x-4)/6 =1

\frac{x + 2}{3} + \frac{x - 4}{6} = 1

x = 2

Solution steps

\frac{x + 2}{3} + \frac{x - 4}{6} = 1

Multiply by LCM

2 (x + 2) + x - 4 = 6

Expand

2 (x + 2) + x - 4 : 3 x

3 x = 6

Divide both sides by

3

x = 2

3 (x + 5) - 2 (2 x + 3) = 7 x + 9

8 x - 5 = 4 x + 11

q, p = 48 - 3 q

(5.9) m = 3

\frac{x}{3} = \frac{12}{4}

What is the answer to (x+2)/3+(x-4)/6 =1 ?
The answer to (x+2)/3+(x-4)/6 =1 is x=2
Solve for x: (x+2)/3+(x-4)/6 =1
The solution is x=2