What is the answer to solvefor a,f=ax^2+bx ?

The answer to solvefor a,f=ax^2+bx is a=(f-bx)/(x^2);\quad x\ne 0

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solvefor a,f=ax^2+bx

solve for

a, f = a x^{2} + b x

a = \frac{f - b x}{x ^{2}}; x \neq = 0

Solution steps

f = a x^{2} + b x

Switch sides

a x^{2} + b x = f

Move

b x

to the right side

a x^{2} = f - b x

Divide both sides by

x^{2}; x \neq = 0

a = \frac{f - b x}{x ^{2}}; x \neq = 0

b, y = b x^{n}

2 x - 4 = 20

x, y - 2 = - 2 (x - 1)

1 = x + 2

6 = 2 - 2 x + 10

What is the answer to solvefor a,f=ax^2+bx ?
The answer to solvefor a,f=ax^2+bx is a=(f-bx)/(x^2);\quad x\ne 0