What is the answer to solvefor k,Y=(kN)/(1+N^2) ?

The answer to solvefor k,Y=(kN)/(1+N^2) is k=(Y(1+N^2))/N ;\quad N\ne i,N\ne-i,N\ne 0

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solvefor k,Y=(kN)/(1+N^2)

solve for

k, Y = \frac{k N}{1 + N ^{2}}

k = \frac{Y ( 1 + N ^{2} )}{N}; N \neq = i, N \neq = - i, N \neq = 0

Solution steps

Y = \frac{k N}{1 + N ^{2}}

Switch sides

\frac{k N}{1 + N ^{2}} = Y

Multiply both sides by

1 + N^{2}

k N = Y (1 + N^{2}); N \neq = i, N \neq = - i

Divide both sides by

N; N \neq = i, N \neq = - i, N \neq = 0

k = \frac{Y ( 1 + N ^{2} )}{N}; N \neq = i, N \neq = - i, N \neq = 0

7 w - 9 = 13 - 4 w

2 t - (t + 2) = 6

x, 3 y - 10 = - 5 x + 4

lo g_{2} (16) = x

lo g_{a} (b) - lo g_{a} (8) = x

What is the answer to solvefor k,Y=(kN)/(1+N^2) ?
The answer to solvefor k,Y=(kN)/(1+N^2) is k=(Y(1+N^2))/N ;\quad N\ne i,N\ne-i,N\ne 0