What is the answer to (2-x)^2-(x+1)(x-6)= 1/2 ?

The answer to (2-x)^2-(x+1)(x-6)= 1/2 is x=-19/2

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(2-x)^2-(x+1)(x-6)= 1/2

(2 - x)^{2} - (x + 1) (x - 6) = \frac{1}{2}

x = - \frac{19}{2}

Decimal Notation

x = - 9.5

Solution steps

(2 - x)^{2} - (x + 1) (x - 6) = \frac{1}{2}

Expand

(2 - x)^{2} - (x + 1) (x - 6) : x + 10

x + 10 = \frac{1}{2}

Move

10

to the right side

x = - \frac{19}{2}

\frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 13

y, 5 x + 2 y = 1

3 (x + 2) = 9

4 (2 r + 3) = 15 r - 11 + 1 - 7 r

\frac{x}{- 4} = - 20

What is the answer to (2-x)^2-(x+1)(x-6)= 1/2 ?
The answer to (2-x)^2-(x+1)(x-6)= 1/2 is x=-19/2
Solve for x: (2-x)^2-(x+1)(x-6)= 1/2
The solution is x=-19/2