What is the answer to solvefor x,(2x-1)/2-(2x+y-2)/3 =(x+2)/6 ?

The answer to solvefor x,(2x-1)/2-(2x+y-2)/3 =(x+2)/6 is x=2y+1

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solvefor x,(2x-1)/2-(2x+y-2)/3 =(x+2)/6

solve for

x, \frac{2 x - 1}{2} - \frac{2 x + y - 2}{3} = \frac{x + 2}{6}

x = 2 y + 1

Solution steps

\frac{2 x - 1}{2} - \frac{2 x + y - 2}{3} = \frac{x + 2}{6}

Multiply by LCM

3 (2 x - 1) - 2 (2 x + y - 2) = x + 2

Expand

3 (2 x - 1) - 2 (2 x + y - 2) : 2 x + 1 - 2 y

2 x + 1 - 2 y = x + 2

Move

2 y

to the right side

2 x + 1 = x + 2 + 2 y

Move

1

to the right side

2 x = x + 2 y + 1

Move

x

to the left side

x = 2 y + 1

2 (3 r + 4) - 3 (r + 1) = 11

\frac{3}{4} a - q = k

3 (x + 5) = 6

- 5 x - 16 + 3 x = - 23 - 9 x

ln (16) = x

What is the answer to solvefor x,(2x-1)/2-(2x+y-2)/3 =(x+2)/6 ?
The answer to solvefor x,(2x-1)/2-(2x+y-2)/3 =(x+2)/6 is x=2y+1