What is the answer to solvefor x,y-1= 2/3 (x+3) ?

The answer to solvefor x,y-1= 2/3 (x+3) is x=(3y-3)/2-3

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solvefor x,y-1= 2/3 (x+3)

solve for

x, y - 1 = \frac{2}{3} (x + 3)

x = \frac{3 y - 3}{2} - 3

Solution steps

y - 1 = \frac{2}{3} (x + 3)

Switch sides

\frac{2}{3} (x + 3) = y - 1

Multiply both sides by

3

2 (x + 3) = 3 y - 3

Divide both sides by

2

x + 3 = \frac{3 y - 3}{2}

Move

3

to the right side

x = \frac{3 y - 3}{2} - 3

\frac{2 ( x + 1 )}{3} - \frac{3 ( x + 2 )}{4} = \frac{( x + 1 )}{6}

x - 2 = - 6

x, 2 x + y - 7 = 0

x, 3 x + 3 y = - 15

\frac{3}{4} b + 9 = 21

What is the answer to solvefor x,y-1= 2/3 (x+3) ?
The answer to solvefor x,y-1= 2/3 (x+3) is x=(3y-3)/2-3