What is the answer to (2x+1)(x-1)+x^2=3(x-1)(x+2)-3 ?

The answer to (2x+1)(x-1)+x^2=3(x-1)(x+2)-3 is x=2

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(2x+1)(x-1)+x^2=3(x-1)(x+2)-3

(2 x + 1) (x - 1) + x^{2} = 3 (x - 1) (x + 2) - 3

x = 2

Solution steps

(2 x + 1) (x - 1) + x^{2} = 3 (x - 1) (x + 2) - 3

Expand

(2 x + 1) (x - 1) + x^{2} : 3 x^{2} - x - 1

Expand

3 (x - 1) (x + 2) - 3 : 3 x^{2} + 3 x - 9

3 x^{2} - x - 1 = 3 x^{2} + 3 x - 9

Move

1

to the right side

3 x^{2} - x = 3 x^{2} + 3 x - 8

Subtract

3 x^{2} + 3 x

from both sides

3 x^{2} - x - (3 x^{2} + 3 x) = 3 x^{2} + 3 x - 8 - (3 x^{2} + 3 x)

Simplify

- 4 x = - 8

Divide both sides by

- 4

x = 2

- 4 = 2.6 x - 1.4

5 x - 2 x + (- x + 6) = 18 - [- (7 x + 6) - (3 x - 24)]

\frac{5 d - 2}{4} + 2 = \frac{8}{5}

30 + y = 38

\frac{14}{16} = \frac{x}{24}

What is the answer to (2x+1)(x-1)+x^2=3(x-1)(x+2)-3 ?
The answer to (2x+1)(x-1)+x^2=3(x-1)(x+2)-3 is x=2
Solve for x: (2x+1)(x-1)+x^2=3(x-1)(x+2)-3
The solution is x=2