What is the answer to solvefor x,(2(x+1))/3-y=-3 ?

The answer to solvefor x,(2(x+1))/3-y=-3 is x=(-9+3y)/2-1

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solvefor x,(2(x+1))/3-y=-3

solve for

x, \frac{2 ( x + 1 )}{3} - y = - 3

x = \frac{- 9 + 3 y}{2} - 1

Solution steps

\frac{2 ( x + 1 )}{3} - y = - 3

Move

y

to the right side

\frac{2 ( x + 1 )}{3} = - 3 + y

Multiply both sides by

3

2 (x + 1) = - 9 + 3 y

Divide both sides by

2

x + 1 = \frac{- 9 + 3 y}{2}

Move

1

to the right side

x = \frac{- 9 + 3 y}{2} - 1

2 x + 2 = 3 x - 3

x, y - 3 = 4 (x - 2)

x, 3 x - 6 y = 3

x, 8 x + y = 0

lo g_{9} (25) = lo g_{9} (5)

What is the answer to solvefor x,(2(x+1))/3-y=-3 ?
The answer to solvefor x,(2(x+1))/3-y=-3 is x=(-9+3y)/2-1