What is the answer to solvefor x,(b-cx)/a+(a-cx)/b+2=0 ?

The answer to solvefor x,(b-cx)/a+(a-cx)/b+2=0 is x=(b+a)/c ;\quad ba\ne 0,b\ne-a

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solvefor x,(b-cx)/a+(a-cx)/b+2=0

solve for

x, \frac{b - c x}{a} + \frac{a - c x}{b} + 2 = 0

x = \frac{b + a}{c}; ba \neq = 0, b \neq = - a

Solution steps

\frac{b - c x}{a} + \frac{a - c x}{b} + 2 = 0

Multiply by LCM

b (b - c x) + a (a - c x) + 2 ba = 0; ba \neq = 0

Expand

b (b - c x) : b^{2} - b c x

b^{2} - b c x + a (a - c x) + 2 ba = 0

Expand

a (a - c x) : a^{2} - c a x

b^{2} - b c x + a^{2} - c a x + 2 ba = 0; ba \neq = 0

Move

b^{2}

to the right side

- b c x + a^{2} - c a x + 2 ba = - b^{2}; ba \neq = 0

Move

a^{2}

to the right side

- b c x - c a x + 2 ba = - b^{2} - a^{2}; ba \neq = 0

Move

2 ba

to the right side

- b c x - c a x = - b^{2} - a^{2} - 2 ba; ba \neq = 0

Factor

- b c x - c a x : - c x (b + a)

- c x (b + a) = - b^{2} - a^{2} - 2 ba; ba \neq = 0

Divide both sides by

- c (b + a); ba \neq = 0, b \neq = - a

x = \frac{b + a}{c}; ba \neq = 0, b \neq = - a

x, 3 x + y = 21

x, 3 x + y = - 8

3 x - 4 = (2 x - 3) + (2 x + 1)

- 24 - \frac{1}{8} p = \frac{3}{8} p

- \frac{3}{2} x = - 1

What is the answer to solvefor x,(b-cx)/a+(a-cx)/b+2=0 ?
The answer to solvefor x,(b-cx)/a+(a-cx)/b+2=0 is x=(b+a)/c ;\quad ba\ne 0,b\ne-a