What are the solutions to the equation 25x^2-60x+36=0 ?

The solutions to the equation 25x^2-60x+36=0 are x= 6/5

Find the zeros of 25x^2-60x+36=0

The zeros of 25x^2-60x+36=0 are x= 6/5

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25 x^{2} - 60 x + 36 = 0

x = \frac{6}{5}

Decimal Notation

x = 1.2

Solution steps

25 x^{2} - 60 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 25 \cdot 36}{2 \cdot 25}

(- 60)^{2} - 4 \cdot 25 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 60 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 60 )}{2 \cdot 25}

\frac{- ( - 60 )}{2 \cdot 25} = \frac{6}{5}

x = \frac{6}{5}

The solution to the quadratic equation is:

x = \frac{6}{5}

x (x - 32) = 0

9 y + 5 = 7 + 3 y + 2 y

\frac{2 - 3}{2 + 3}

\frac{y ^{13}}{y ^{6}}

2 x^{2} = 11 x + 40

What are the solutions to the equation 25x^2-60x+36=0 ?
The solutions to the equation 25x^2-60x+36=0 are x= 6/5
Find the zeros of 25x^2-60x+36=0
The zeros of 25x^2-60x+36=0 are x= 6/5