What is the answer to solvefor y,f=x^3-12x-4y+1 ?

The answer to solvefor y,f=x^3-12x-4y+1 is y=-(f-x^3+12x-1)/4

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solvefor y,f=x^3-12x-4y+1

solve for

y, f = x^{3} - 12 x - 4 y + 1

y = - \frac{f - x ^{3} + 12 x - 1}{4}

Solution steps

f = x^{3} - 12 x - 4 y + 1

Switch sides

x^{3} - 12 x - 4 y + 1 = f

Move

x^{3}

to the right side

- 12 x - 4 y + 1 = f - x^{3}

Move

12 x

to the right side

- 4 y + 1 = f - x^{3} + 12 x

Move

1

to the right side

- 4 y = f - x^{3} + 12 x - 1

Divide both sides by

- 4

y = - \frac{f - x ^{3} + 12 x - 1}{4}

- 3 = \frac{t}{- 15}

x, 4 x + 2 y - 5 = 0

12 k + 15 = 35 + 2 k

x, y - 5 = \frac{2}{3} (x - 3)

0.65 = 0.5 + x - 0.5 \cdot x

What is the answer to solvefor y,f=x^3-12x-4y+1 ?
The answer to solvefor y,f=x^3-12x-4y+1 is y=-(f-x^3+12x-1)/4