What is the answer to (x+2)/3-(2x-4)/2 =0 ?

The answer to (x+2)/3-(2x-4)/2 =0 is x=4

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(x+2)/3-(2x-4)/2 =0

\frac{x + 2}{3} - \frac{2 x - 4}{2} = 0

x = 4

Solution steps

\frac{x + 2}{3} - \frac{2 x - 4}{2} = 0

Multiply by LCM

2 (x + 2) - 6 (x - 2) = 0

Expand

2 (x + 2) - 6 (x - 2) : - 4 x + 16

- 4 x + 16 = 0

Move

16

to the right side

- 4 x = - 16

Divide both sides by

- 4

x = 4

8 - 2 x = 30

3 (a + 1) - 5 = 3 a - 2

12 = \frac{5}{2} b

c, 5 e^{x} - 9 cos (x) = 2

- 8 = - 3 + \frac{m}{3}

What is the answer to (x+2)/3-(2x-4)/2 =0 ?
The answer to (x+2)/3-(2x-4)/2 =0 is x=4
Solve for x: (x+2)/3-(2x-4)/2 =0
The solution is x=4