What is the answer to x+4-(x-2)(x-1)=3(3-x)-x^2 ?

The answer to x+4-(x-2)(x-1)=3(3-x)-x^2 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+4-(x-2)(x-1)=3(3-x)-x^2

x + 4 - (x - 2) (x - 1) = 3 (3 - x) - x^{2}

x = 1

Solution steps

x + 4 - (x - 2) (x - 1) = 3 (3 - x) - x^{2}

Expand

3 (3 - x) : 9 - 3 x

- x^{2} + 4 x + 2 = 9 - 3 x - x^{2}

Expand

x + 4 - (x - 2) (x - 1) : - x^{2} + 4 x + 2

- x^{2} + 4 x + 2 = 9 - 3 x - x^{2}

Move

2

to the right side

- x^{2} + 4 x = - x^{2} - 3 x + 7

Subtract

- x^{2} - 3 x

from both sides

- x^{2} + 4 x - (- x^{2} - 3 x) = - x^{2} - 3 x + 7 - (- x^{2} - 3 x)

Simplify

7 x = 7

Divide both sides by

7

x = 1

y, 2 x y + 6 y = 10

x, - 7 x + 7 y = 21

x, - 4 x - y = - 2

f, y = 2 - f

\frac{5}{8} (4 x - 16) = 20

What is the answer to x+4-(x-2)(x-1)=3(3-x)-x^2 ?
The answer to x+4-(x-2)(x-1)=3(3-x)-x^2 is x=1
Solve for x: x+4-(x-2)(x-1)=3(3-x)-x^2
The solution is x=1